Wade Leftwich wrote: > from itertools import groupby > > def chunk(it, n=0): > if n == 0: > return iter([it]) > def groupfun((x,y)): > return int(x/n) > grouped = groupby(enumerate(it), groupfun) > counted = (y for (x,y) in grouped) > return ((z for (y,z) in x) for x in counted) > >>>> [list(x) for x in chunk(range(10), 3)] > [[0, 1, 2], [3, 4, 5], [6, 7, 8], [9]] > >>>> [x for x in chunk(range(10), 3)] > [<generator object at 0xb7a34e4c>, > <generator object at 0xb7a34dac>, > <generator object at 0xb7a34d2c>, > <generator object at 0xb7a34d6c>]
Note that all but the last of these generators are useless: >>> chunks = [x for x in chunk(range(10), 3)] >>> [list(x) for x in chunks] [[], [], [], [9]] # did you expect that? Peter -- http://mail.python.org/mailman/listinfo/python-list
