Michael M. schrieb: > How to find the longst element list of lists? > > I think, there should be an easier way then this: > > s1 = ["q", "e", "d"] > s2 = ["a", "b"] > s3 = ["a", "b", "c", "d"] > > if len(s1) >= len(s2) and len(s1) >= len(s3): > sx1=s1 ## s1 ist längster > if len(s2) >= len(s3): > sx2=s2 > sx3=s3 > else: > sx2=s3 > sx3=s2 > > if len(s2) >= len(s3) and len(s2) >= len(s1): > sx1=s2 ## s2 ist längster > if len(s3) >= len(s1): > sx2=s3 > sx3=s1 > else: > sx2=s1 > sx3=s3 > > if len(s3) >= len(s1) and len(s3) >= len(s2): > sx1=s3 ## s3 ist längster > if len(s1) >= len(s2): > sx2=s1 > sx3=s2 > else: > sx2=s2 > sx3=s1 > > After, the list ist sorted: > > sx1 = ["a", "b", "c", "d"] > sx2 = ["q", "e", "d"] > sx3 = ["a", "b"] >
I don't really get that. You have three lists, you want to sort them after their length. You should put them into one list. I think you should rather implement this as: >>> list = [a1, s2, s3] >>> list.sort(lambda x,y: cmp(len(y), len(x))) >>> list [['a', 'b', 'c', 'd'], ['q', 'e', 'd'], ['a', 'b']] Thomas -- http://mail.python.org/mailman/listinfo/python-list
