robert <[EMAIL PROTECTED]> wrote: > shellon wrote: >> Hi all: >> I want to convert the float number to sortable integer, like the >> function float2rawInt() in java, but I don't know the internal >> expression of float, appreciate your help! >> > > float comparision works well enough for sorting in Python. What is > the actual requirement? >
Maybe this is the problem? >>> sorted([-0.0, 0.0, -0.0, 0.0, -0.0]) [-0.0, 0.0, -0.0, 0.0, -0.0] Java sorting imposes an artificial total ordering on float or double values: > The < relation does not provide a total order on all floating-point > values; although they are distinct numbers -0.0 == 0.0 is true and a > NaN value compares neither less than, greater than, nor equal to any > floating-point value, even itself. To allow the sort to proceed, > instead of using the < relation to determine ascending numerical > order, this method uses the total order imposed by > Double.compareTo(java.lang.Double). This ordering differs from the < > relation in that -0.0 is treated as less than 0.0 and NaN is > considered greater than any other floating-point value. For the > purposes of sorting, all NaN values are considered equivalent and > equal. -- http://mail.python.org/mailman/listinfo/python-list
