Re: converting u'11\xa022' to '11\xa022'

[Jean-Paul Calderone]

On Tue, 20 Feb 2007 18:12:42 -0600, alf <[EMAIL PROTECTED]> wrote:
>Hi,
>is there a more elegant way to do that:
>
>''.join([chr(ord(i)) for i in u'11\xa022' ])
>

  u'11\xa022'.encode('charmap')

Jean-Paul
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