James Stroud wrote:
> [EMAIL PROTECTED] wrote:
>
>> Hi all--
>>
>> Trying to learn Python w/little more than hobbyist (bordering on pro/
>> am, I guess) Perl as a background.
>>
>> My problem is, I have a list of departments, in this instance, things
>> like "Cheese", "Bakery", et al. (I work @ a co-op health food store).
>> I've populated a list, 'depts', w/these, so that their indexes match
>> our internal indexing (which skips a few #'s).
>>
>> Now, I'd like to simply generate-- and be able to refer to-- a bunch
>> of other lists-sets (for subdepartments) by iterating through this
>> list, and naming each of these subdepartment lists "categoryx", where
>> x is the index # from the master 'depts' list. And then be able to
>> populate & refer to these lists by accessing their variable-including
>> name.
>>
>> In Perl, it's a fairly trivial matter to use a string variable in
>> naming some other kind of variable-- not sure about Python though. My
>> initial, very weak stab at it (don't laugh!) went something like this:
>>
>> for i in range(len(depts)):
>> if depts[i]:
>> categorylistdeptname = 'category' + str(i)
>> categorylistdeptname = []
>>
>> Not sure what that wound up doing, but it sure didn't seem to work.
>
>
> First, your are rebinding categorylistdeptname in the loop every time.
>
> But you probably want a dict (in python 2.4 or later):
>
>
> deptdict = dict((dept, []) for dept in depts))
>
> And this gets what you want, believe it or not.
>
> Now you can populate each list:
>
> deptdict['Bakery'].append("Donuts")
> deptdict['Bulk'].extend(["Granola", "Rasins"])
>
> And work witht the lists by name:
>
> for item in deptdict['Bulk']:
> print item
> # prints "Granola", "Rasins", etc.
>
>
> James
>
Typo, too many parens. Should be:
deptdict = dict((dept, []) for dept in depts)
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