bahoo a écrit :
> Hi,
>
> I have a text file containing a single line of text, such as
> 0024
>
> How should I read it into a "list"?
You mean ['0024'], or ['0', '0', '2', '4'] ?
> I tried this, but the "join" did not work as expected.
What did you expect ?
help(str.join)
join(...)
S.join(sequence) -> string
Return a string which is the concatenation of the strings in the
sequence. The separator between elements is S.
> Any
> suggestions?
Honestly, the first would be to learn to ask questions, and the second
to pay more attention to what's written in the doc. But let's try :
> infile = open('my_file.txt','r')
> for line in infile:
> line.join(line)
> my_list.extend( line )
>
If you have a single line of text, you don't need to iterate.
file has a readlines() method that will return a list of all lines. It
also has a read() method that reads the whole content. Notice that none
of these methods will strip newlines characters.
Also, str has a strip() method that - by default - strip out any
'whitespace' characters - which includes newline characters. And
finally, passing a string as an argument to list's constructor gives you
a list of the characters in the string.
This is all you need to know to solve your problem - or at least the two
possible definitions of it I mentionned above.
>>> open('source.txt').readlines()
['0024\n']
>>> map(str.strip, open('source.txt').readlines())
['0024']
>>> open('source.txt').read()
'0024\n'
>>> list(open('source.txt').read().strip())
['0', '0', '2', '4']
>>>
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