James Stroud wrote:
> Andy wrote:
>> Hi, the file below will print all the keywords in a file and also the
>> line # of the keyword. What I couldn't figure out is to count those
>> keywords per line. For example - "Line #1 has 3 keywords"
>>
>> Can I do like -
>>
>> total[j] = total[j] + numwords(k)
>> "Line number %d has %d keywords" % (j, total[j])
>>
>> Seems sort of "illegal" in Python?
>>
>>
>>
>> -------------------------------------------------
>> import keyword, sys, string, fileinput
>> def numwords(s):
>> list = string.split(s)
>> return len(list)
>>
>> # Get the file name either from the command-line or the user
>> if len(sys.argv) != 2:
>> name = raw_input("Enter the file name: ")
>> else:
>> name = sys.argv[1]
>>
>> inp = open(name,"r")
>> linelist = inp.readlines()
>> total, words,lines = 0, 0, 0
>>
>> for i in range(len(linelist)):
>> line = linelist[i]
>> tempwords = line.split()
>> for k in tempwords:
>> if keyword.iskeyword(k):
>> total = total + numwords(k)
>> j = i + 1
>> print" The word * %s * belongs in line number: %d" % (k,
>> j)
>>
>> print "Total keywords in this file are: %d" %(total)
>>
>
> You probably want something that goes a little like this:
>
> for i,line in enumerate(linelist):
> for k in line.split():
> if keyword.iskeyword(k):
> total += line.count(k)
> print "The word '%s' belongs in line num: %d" % (k, i+1)
>
> print "Total keyords are: %d" % total
>
> James
Oops, that over-counts, I forgot to put a continue in. Also, keeping a
cache of the split line will probably be faster.
for i,line in enumerate(linelist):
line = line.split()
for k in line:
if keyword.iskeyword(k):
total += line.count(k)
print "The word '%s' belongs in line num: %d" % (k, i+1)
continue
print "Total keyords are: %d" % total
James
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