Dave Borne wrote:
Let's suppose
s='12345 4343 454'
How can I replace the last '4' character?
If the last '4' will not always be the last character in the string,
you could do:
'X'.join(s.rsplit('4',1))
from string import rfind
def replaceLast_X_with_Y( s, x, y ):
lastX = s.rfind(x)
return s[:lastX]+ y + s[lastX+1:]
s = '12345 4343 454'
replaceLast_X_with_Y( s, '4', '9' )
'12345 4343 459'
sph
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