[EMAIL PROTECTED] wrote:
> Hi,
> Suppose i have a list v which collects some numbers,how do i
> remove the common elements from it ,without using the set() opeartor.
Is this a test? Why don't you want to use the set operator?
Anyway, you can just move things from one list into another
excluding those which are already moved:
<code>
numbers = [1, 2, 3, 3, 4, 4, 5]
unique_numbers = []
for n in numbers:
if n not in unique_numbers:
unique_numbers.append (n)
print unique_numbers
</code>
It won't be the fastest thing you could do, but it
does work. Using a dictionary would speed things up,
but then you're basically implementing a set using
a dictionary.
TJG
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