In message <[EMAIL PROTECTED]>, Carl
Banks wrote:
> Consider this: is there any other code in your program that has to do
> something different based on whether you successfully opened this file
> or not? If so, how will you notify it whether the call has succeeded
> or not? Very often, the caller itself needs to know. You could, say,
> set a flag to indicate it's failed, but why do that when you could
> simply let the caller detect and handle the error itself?
I am generally wary of exceptions, and like to contain them as much as
possible. So my answer to your point is something like
try :
f = open(TheFile, "r")
except IOError, (ErrNo, Msg) :
if ErrNo != errno.ENOENT :
raise
#end if
f = None
#end try
(Note how I check for the specific error code I want to handle.) Then later
on I can determine if the file was successfully opened by
if f != None :
... further processing on f ...
#end if
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