Bruno Desthuilliers wrote:
> mr_gadget a écrit :
>> When I create a subfolder, python is not seeing it. Can someone please
>> explain this behaviour ? I just started with python, read the tutorial over
>> the weekend and am writing my very first script. So I may not be seeing
>> something. Both os.path and glob.glob seem not to see a folder I created.
>> Other sibling folders seem to work fine. On a whim I tried paths with \\
>> double slashes and that worked. But why should single slashes work for some
>> folders and not for others ??
>
Note you *didn't* try paths with double slashes, you merely correctly
represented the paths with single slashes :-)
> s/slash/antislash/g
>
> It's a very well known gotcha due to MS's choice to use the antislash as
> path separator. In most languages - Python included - the antislash is
> used for escape sequences (non-printable characters). '\r' is the escape
> sequence for CR (carriage return). Doubling the antislash prevents
> escaping.
>
> You can avoid all escaping by using raw strings:
>
> mypath = r"C:\enhancement\rawfiles\"
>
Please note that the above is a well-known syntax error. A string
literal cannot end with a single backslash, as it escapes the closing quote.
>>> mypath = r"C:\enhancement\rawfiles\"
File "<stdin>", line 1
mypath = r"C:\enhancement\rawfiles\"
^
SyntaxError: EOL while scanning single-quoted string
>>>
> Also and IIRC, using slash instead should also work, ie:
>
> mypath = r"C:/enhancement/rawfiles/"
>
That does indeed work in most situations, but ideally (i.e. for maximum
code portability) paths should be constructed using os.path.join(), or
collected from the environment somehow.
regards
Steve
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