On Fri, 07 Sep 2007 06:57:35 -0700, cjt22 wrote:
> I have a step class and store in a list step instances
> A step instance contains variables: name, startTime etc and startTime
> is stored as a string %H:%M:%S
>
> What I would like to do is to be able to sort this list of objects
> based on the startTime object so that the first item in the list is
> the object with the earliest Start time and last item is the object
> with the last Start time.
>
> I belive my key has to be = strpTime(step.sTime, "%H:%M:%S")
> But don't know how to create the comparison funciton.
>
> Any help on how I can perform this whole operation would be much
> appreciated.
This should be enough::
steps.sort(key=lambda s: s.startTime)
If you sort strings of the form 'hh:mm:ss' the represented times are
sorted chronological. No need to convert them to a number first.
If the "natural" sort criterion for `Step` objects is the start time you
might override `__cmp__()` of `Step`\s instead::
def __cmp__(self, other):
return cmp(self.startTime, other.startTime)
Now you can just sort the list with ``steps.sort()``.
Ciao,
Marc 'BlackJack' Rintsch
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