En Fri, 07 Sep 2007 00:02:12 -0300, Ben Warren <[EMAIL PROTECTED]>
escribi�:
> Hello,
>
> Let's say I have a function with a variable number of arguments (please
> ignore syntax errors):
>
> def myfunc(a,b,c,d,...):
>
> and I have a tuple whose contents I want to pass to the function. The
> number of elements in the tuple will not always be the same.
>
> T = A,B,C,D,...
>
> Is there a way that I can pass the contents of the tuple to the function
> without explicitly indexing the elements? Something like:
>
> myfunc(magic(T))
Use *T when calling the function:
py> def myfunc(a, b, c, d=None, e=None):
... print a,b,c,d,e
...
py> T = 1,2,3,4,5
py> myfunc(*T)
1 2 3 4 5
py> T = 1,2,3
py> myfunc(*T)
1 2 3 None None
py> T = 1,2
py> myfunc(*T)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: myfunc() takes at least 3 arguments (2 given)
A similar syntax works when defining a function: *args will receive all
remaining positional arguments joined into a tuple:
py> def otherfunc(a, b, *args):
... print a, b, args
...
py> otherfunc(1,2,3,4,5)
1 2 (3, 4, 5)
py> T = 1,2,3,4
py> otherfunc(*T)
1 2 (3, 4)
py> otherfunc('a','b','c',*T)
a b ('c', 1, 2, 3, 4)
This is covered in the Python Tutorial at
<http://docs.python.org/tut/node6.html#SECTION006700000000000000000> and
you can read the nasty details here <http://docs.python.org/ref/calls.html>
--
Gabriel Genellina
--
http://mail.python.org/mailman/listinfo/python-list
