Rustom Mody wrote: > On 9/16/07, cesco <[EMAIL PROTECTED]> wrote: >> Hi, >> >> is there a one-liner to accomplish the following task? >> >From the list >> l = ['string1', 'string2', 'string3'] >> generate the list of lists >> l = [['string1'], ['string1', 'string2'], ['string1', 'string2', >> 'string3']] >> >> Any help would be appreciated. >> >> Thanks >> Francesco >>>> l = [1,2,3,4,5] > >>>> [l[:i] for i in range(len(l))] > [[], [1], [1, 2], [1, 2, 3], [1, 2, 3, 4]] > well almost works except for the first empty list. [Are you sure you > dont want it?] > > Corrected > >>>> [l[:i+1] for i in range(len(l)-1)] > [[1], [1, 2], [1, 2, 3], [1, 2, 3, 4]] > > Though I wonder if there is as neat a way as the first?
>>> [l[:i] for i in range(1, len(l))] [[1], [1, 2], [1, 2, 3], [1, 2, 3, 4]] >>> seems a slightly neater way to meet the requirement. regards steve -- Steve Holden +1 571 484 6266 +1 800 494 3119 Holden Web LLC/Ltd http://www.holdenweb.com Skype: holdenweb http://del.icio.us/steve.holden Sorry, the dog ate my .sigline -- http://mail.python.org/mailman/listinfo/python-list
