Hrvoje Niksic <[EMAIL PROTECTED]> writes: > class X(Y): > def foo(self): > super(X, self).foo() > > ...there is in fact no guarantee that super() calls a superclass of > X. However, it is certainly guaranteed that it will call a superclass > of type(self).
Not even that. It could call *any class in the inheritance hierarchy*, depending on how the MRO has resolved "next class". Even one that is neither an ancestor nor a descendant of X. -- \ "When I was a kid I used to pray every night for a new bicycle. | `\ Then I realised that the Lord doesn't work that way so I stole | _o__) one and asked Him to forgive me." -- Emo Philips | Ben Finney -- http://mail.python.org/mailman/listinfo/python-list
