On Sep 24, 2:42 pm, [EMAIL PROTECTED] wrote: > Here's how I'm doing this right now, It's a bit slow. I've just got > the code working. I was wondering if there is a more efficient way of > doing this... simple example from interactive Python: > > >>> word = '' > >>> hexs = ['42', '72', '61', '64'] > >>> for h in hexs: > > ... char = unichr(int(h, 16)) > ... word += char > ... print char > ... > B > r > a > d>>> print word > > Brad > > Each hex_number is two digits. unichr converts that to a character > that I append to previous ints that have been converted to chars. In > this way, I convert a string of hex numbers to ints to letters, to > words.
The cleanest code is: word = ''.join(unichr(int(h, 16)) for h in hexs) If you want fast, you can build a cache once that maps hex strings to unicode characters something like this: cache = dict((hex(i)[2:], unichr(i)) for i in range(256)) Then use something like your code: word = '' for h in hexs: word += cache[h] Or a list comprehension: word = ''.join([cache[h] for h in hexs]) Or a generator: word = ''.join(cache[h] for h in hexs) -- Paul Hankin -- http://mail.python.org/mailman/listinfo/python-list
