termiflyer wrote:
> How do I sort this:
>
>>>> a
> [['3', ['1', '0']], ['4', ['3', '0'], ['2', '0']]]
>
> where the list can be arbitrarily large by the 3rd dimension (i
> think). E.g.:
>
>>>> a
> [['3', ['1', '0']], ['4', ['2', '0'], ['3', '0']]]
>
>
> Thanks
>
Your difficulties come from an ill-defined third dimension. You should
reorganize to produce this heretofore potential third dimension:
a = [(i[0], i[1:]) for i in a]
Then sort the reorganized list now that it has a structure amenable to
sorting:
for i in a:
i[1].sort()
Then, if you are pressed, transform it back:
a = [[i[0]] + i[1] for i in a]
E.g.:
py> a = [['3', ['1', '0']], ['4', ['3', '0'], ['2', '0']]]
py> a = [(i[0], i[1:]) for i in a]
py> a
[('3', [['1', '0']]), ('4', [['3', '0'], ['2', '0']])]
py> for i in a:
... i[1].sort()
...
py> a
[('3', [['1', '0']]), ('4', [['2', '0'], ['3', '0']])]
py> a = [[i[0]] + i[1] for i in a]
py> a
[['3', ['1', '0']], ['4', ['2', '0'], ['3', '0']]]
James
--
James Stroud
UCLA-DOE Institute for Genomics and Proteomics
Box 951570
Los Angeles, CA 90095
http://www.jamesstroud.com
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