On Oct 15, 12:33 pm, Michele Simionato <[EMAIL PROTECTED]> wrote: > is a design decision, in the sense that Python always do late binding. > If you
> you will get funclist[0]() == funclist[1]() == funclist[2]() == 3 (you > get the latest > binding of "i"). As you see, it has nothing to do with lambdas. > Thanks Diez, replacing my addCallback with d.addCallback(lambda result, comp=c: comp.compile()) do the trick. So if I understand what Michele wrote (thanks too), when a function is defined (with def), no scope is saved and every variable value not passed in parameter is lost ? It means that variable value come from the outer scope when the function is called ? -- http://mail.python.org/mailman/listinfo/python-list
