Jean-Paul Calderone wrote: > On Sat, 20 Oct 2007 21:10:34 +0200 (CEST), sccs cscs <[EMAIL PROTECTED]> > wrote: >> Hello, >> I cannot find into documentation how to get the instance name. I found >> the attributes __dict__,__class__ ,__bases__ __name__ , >> but if i have the code: >> >> class A :pass >> a1 = A () >> a2 = A () >> aList = [a1,a2] >> for elem in aList : >> print elem.__instance_name__ ??? >> >> I expect to have "a1" "a2" ... >> But it does not work ... >> help please >> Zorgi > > $ python > Python 2.4.3 (#2, Oct 6 2006, 07:52:30) > [GCC 4.0.3 (Ubuntu 4.0.3-1ubuntu5)] on linux2 > Type "help", "copyright", "credits" or "license" for more information. > >>> class A: pass > ... > >>> a1 = A() > >>> a2 = A() > >>> aList = [a1, a2] > >>> import __main__ > >>> from twisted.python.reflect import objgrep, isSame > >>> for elem in aList: > ... objgrep(__main__, elem, isSame) > ... > ['.aList[0]', '.elem', '.a1'] > ['.aList[1]', '.elem', '.a2'] > >>> > > Don't see how this could help, > > Jean-Paul If you want to accomplish something like this use the following:
class A(object): def __init__(self, name=None): self.name=name aList=[] aList.append(A(name='a1') aList.append(A(name='a2') for elem in aList: print elem.name -Larry -- http://mail.python.org/mailman/listinfo/python-list