Re: Multiline regex help

[Steven Bethard]

Yatima wrote:
On Thu, 03 Mar 2005 09:54:02 -0700, Steven Bethard <[EMAIL PROTECTED]> wrote:
A possible solution, using the re module:
py> s = """\
... Gibberish
... 53
... MoreGarbage
... 12
... RelevantInfo1
... 10/10/04
... NothingImportant
... ThisDoesNotMatter
... 44
... RelevantInfo2
... 22
... BlahBlah
... 343
... RelevantInfo3
... 23
... Hubris
... Crap
... 34
... """
py> import re
py> m = re.compile(r"""^RelevantInfo1\n([^\n]*)
...                    .*
...                    ^RelevantInfo2\n([^\n]*)
...                    .*
...                    ^RelevantInfo3\n([^\n]*)""",
...                re.DOTALL | re.MULTILINE | re.VERBOSE)
py> score = {}
py> for info1, info2, info3 in m.findall(s):
...     score.setdefault(info1, {})[info3] = info2
...
py> score
{'10/10/04': {'23': '22'}}
Note that I use DOTALL to allow .* to cross line boundaries, MULTILINE 
to have ^ apply at the start of each line, and VERBOSE to allow me to 
write the re in a more readable form.

If I didn't get your dict update quite right, hopefully you can see how 
to fix it!

Thanks! That was very helpful. Unfortunately, I wasn't completely clear when
describing the problem. Is there anyway to extract multiple scores from the
same file and from multiple files
I think if you use the non-greedy .*? instead of the greedy .*, you'll 
get this behavior.  For example:

py> s = """\
... Gibberish
... 53
... MoreGarbage
[snip a whole bunch of stuff]
... RelevantInfo3
... 60
... Lalala
... """
py> import re
py> m = re.compile(r"""^RelevantInfo1\n([^\n]*)
...                    .*?
...                    ^RelevantInfo2\n([^\n]*)
...                    .*?
...                    ^RelevantInfo3\n([^\n]*)""",
...                re.DOTALL | re.MULTILINE | re.VERBOSE)
py> score = {}
py> for info1, info2, info3 in m.findall(s):
...     score.setdefault(info1, {})[info3] = info2
...
py> score
{'10/10/04': {'44': '33', '23': '22'}, '10/11/04': {'60': '45'}}
If you might have multiple info2 values for the same (info1, info3) 
pair, you can try something like:

py> score = {}
py> for info1, info2, info3 in m.findall(s):
...     score.setdefault(info1, {}).setdefault(info3, []).append(info2)
...
py> score
{'10/10/04': {'44': ['33'], '23': ['22']}, '10/11/04': {'60': ['45']}}
HTH,
STeVe
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