Peter Decker wrote: > On Nov 28, 2007 7:22 PM, stef mientki <[EMAIL PROTECTED]> wrote: >> print 'xx3',ordered_list.sort() > > The sort() method returns None. It sorts the list in place; it doesn't > return a copy of the sorted list. > Thank you all for the answers, I do understand now, although I find it rather non-intuitive. I didn't expect a copy, but a reference to itself wouldn't be asked too much ? Why does it return None, instead of the sorted object itself ? I guess it would cost almost exactly the same processing power.
cheers, Stef Mientki -- http://mail.python.org/mailman/listinfo/python-list
