Bruno Desthuilliers wrote: > c james a écrit : >> Given a condition at the time a class is instantiated, I want to change >> how __call__ is used. From the example below, self.no is using self.yes >> but self.__call__ is not. Can someone please explain why? > > IIRC, you can't override __magic__ methods on a per-instance basis.
> This should do the trick: > > class YesNo(object): > def __init__(self, which): > self.which = which > > def __call__(self, val): > return (self.no, self.yes)[self.which](val) > > def yes(self, val): > print 'Yes', val > > def no(self, val): > print 'No', val Thanks, I was trying to eliminate another level of indirection with a test at each invocation of __call__ -- http://mail.python.org/mailman/listinfo/python-list
