> Here is sample function:
>
> def a():
> b()
> print c
>
> def b():
> c = "Hi"
> return c
>
> if __name__ == "__main__":
> a()
>
> then run a(). Throws error about c not being defined. How do I return c from
> b?
you *do* return c from b, and within the scope of a(), c is not
defined (within scope) as the error informs you.
However when you call b(), you don't do anything with its return
value. Try
def a():
result = b() # do something with the returned value
print result
yes, there's also a "global" keyword, but it uglifies code and
logic-flow horribily.
-tkc
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