[EMAIL PROTECTED] a écrit :
> I am doing a string.replace in a simple table generation app I wrote,
> and I can't figure out how to match whitespace with /s,
Hahem... Where did you get the idea that str.replace would work with
regexps ?
"""
replace(...)
S.replace (old, new[, count]) -> string
Return a copy of string S with all occurrences of substring
old replaced by new. If the optional argument count is
given, only the first count occurrences are replaced.
"""
See any mention of regexps here ?-)
> so I thought
> I would see if osmeone where would be kind enough to tell me what I am
> getting wrong.
>
>
> This works:
>
> string = string.replace('<tr>\n <th class="table">Field One</th>
> \n <td>%FieldOneValue%</td>\n </tr>', '')
>
>
> You can see I had to actually put in space characters and linefeeds
> exactly as they are in the string.
Indeed. That's consistent with the doc.
> I tried these this:
>
> string = string.replace('<tr>\s*<th class="table">Field One</th>\s*<td>
> %FieldOneValue%</td>\s*</tr>', '')
>
>
> But this doesn't work.
It works if you have *litteraly* the first arg in your string !-)
> The doco for Python's regex suggests that \s
> should match any whitespace including newlines which is what I
> wanted,
So why do you insist on using str.replace insted of re.sub ?-)
> but just in case, I also tried this:
>
> string = string.replace('<tr>\n\s*<th class="table">Field One</th>\n
> \s*<td>%FieldOneValue%</td>\n\s*</tr>', '')
>
>
> Any help explaining why these are not working would be greatly
> appreciated.
import re
pat = r'<tr>\s*<th class="table">Field One</th>\s*<td>' \
+ r'%FieldOneValue%</td>\s*</tr>'
string = re.sub(pat, '', string)
HTH
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