On Dec 26, 10:36 am, t_rectenwald <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I attempting to execute an Oracle query, and write the results to a
> file in CSV format. To do so, I've done the following:
>
> import cx_Oracle
> db = cx_Oracle.connect('user/[EMAIL PROTECTED]')
> cursor = db.cursor()
> cursor.arraysize = 500
> cursor.execute(sql)
> result = cursor.fetchall()
>
> The above works great. I'm able to connect to the database and print
> out the results as a list of tuples. Here is where I get lost. How
> do I work with a "list of tuples?" My understanding is that a "list"
> is basically an array (I don't come from a Python background). Tuples
> are a "collection of objects." So, if I do...
>
> print result[0]
>
> I get the first row of the query, which would make sense. The problem
> is that I cannot seem to write tuples to a file. I then do this...
>
> csvFile = open("output.csv", "w")
> csvFile = write(result[0])
> csvFile.close
>
> This generates an exception:
>
> TypeError: argument 1 must be string or read-only character buffer,
> not tuple
>
> So, I'm a bit confused as to the best way to do this. I guess I could
> try to convert the tuples into strings, but am not sure if that is the
> proper way to go. Any help would be appreciated. I've also seen a
> csv module out there, but am not sure if that is needed in this
> situation.
>
> Best Regards,
> Tom
Hello,
I was able to figure this out by using join to convert the tuples into
strings, and then have those write to the filehandle:
csvFile = open("output.csv", "w")
for row in cursor.fetchall():
csvFile.write(','.join(row) + "\n")
csvFile.close
Regards,
Tom
--
http://mail.python.org/mailman/listinfo/python-list
