[EMAIL PROTECTED] wrote:
> Dear fellow Pythonians,
>
> I just stumbled upon the following unexpected behavior:
>
> class TestType(type):
> def Foo(self): return 'TestType Foo'
> class Test(object):
> __metaclass__ = TestType
> def Foo(self): return 'Test Foo'
> t = Test()
> print t.Foo()
> print Test.Foo()
>
> This will produce:
> Test Foo
> Traceback (most recent call last):
> File "test.py", line 8, in <module>
> print Test.Foo()
> TypeError: unbound method Foo() must be called with Test instance as
> first argument (got nothing instead)
>
> I can imagine why this is happening, and that there is no easy
> solution, but it is not what I was expecting.
>
> Anybody willing to explain the details of what's exactly going on
> during the method lookup of Test.Foo?
The regular method is checked for *before* the metaclass method.
You must use
type(Test).Foo(Test)
to call the method. It is clear that it must be that way: when you do
(for instance)
SomeClass.__init__ you do not expect to have type.__init__(SomeClass)
called.
Notice that *all* classes have a metaclass, by default "type" for new-
style
classes and "ClassType" for old-style ones.
Michele Simionato
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