I'm not sure if this is a bug or if I'm just not understanding
something correctly. I'm running the following (broken.py) on
ActivePython 2.5.1.1, based on Python 2.5.1 (r251:54863 5/1/2007) as
"python broken.py foo" (on Windows, of course):
#!/bin/env python
import sys
class foobar(object):
def func(arg):
print 'foobar.func: %r' % arg
__f = foobar()
def caller(a):
print 'caller: %r' % a
__f.func(a)
def main():
rest = sys.argv[1:]
print 'main: %r' % rest
caller(*rest)
if __name__ == '__main__':
main()
...and the result of running this ("python broken.py foo") is:
main: ['foo']
caller: 'foo'
Traceback (most recent call last):
File "broken.py", line 21, in <module>
main()
File "broken.py", line 18, in main
caller(*rest)
File "broken.py", line 13, in caller
__f.func(a)
TypeError: func() takes exactly 1 argument (2 given)
How can this possibly be? The "caller" print statement obviously
shows "a" is singular.
Thanks in advance for any and all insight...
Mike
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