On Jan 11, 2:57 pm, Paul Rubin <http://[EMAIL PROTECTED]> wrote: > [EMAIL PROTECTED] writes: > > Any ideas for a thread-safe list.removeall( X ): removing all > > occurrences of X within list L, when L might be modified concurrently? > > That way lies madness. Do something sensible instead. Put a lock > around the list, or put all mutators for the list into a single > thread, or whatever. Don't do what you're describing.
This function just wants X out of the list. It doesn't matter if this happens before, during, or after something else; so long as it happens. -- http://mail.python.org/mailman/listinfo/python-list
