> Ok the problem we had been asked a while back, to do a programming > exercise (in college) > That would tell you how many days there are in a month given a > specific month. > > Ok I did my like this (just pseudo): > > If month = 1 or 3 or etc .... > noDays = 31 > Elseif month = 4 or 6 etc .... > noDays = 30 > Else > noDays = 29 > (we didn't have to take into account a leap year) > > He declared an array and assigned the number of days in a month to its > own element in an array. Now > I realise that in this example it would not make a difference in terms > of efficiency, but it is my belief that if > there is more data that needed to be assigned(i.e. a couple megs of > data) it would be simpler (and more efficient) to > do a compare rather then assigning all that data to an array, since > you are only going to be using 1 value and the rest > of the data in the array is useless. > > What are everyone else's thoughts on this?
Well, the standard library offers its opinion: >>> import calendar >>> calendar.mdays [0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31] >>> month = 2 >>> calendar.mdays[month] 28 If you want the actual number of days, taking leap-years into consideration >>> calendar.monthrange(2008,2)[1] 29 >>> calendar.monthrange(2007,2)[1] 28 So the answer is "mu"...let Python do the work for you :) -tkc -- http://mail.python.org/mailman/listinfo/python-list
