En Fri, 15 Feb 2008 17:07:21 -0200, Jonathan Lukens
<[EMAIL PROTECTED]> escribió:
> I am in the last phase of building a Django app based on something I
> wrote in Java a while back. Right now I am stuck on how to return the
> matches of a regular expression as a list *at all*, and in particular
> given that the regex has a number of groupings. The only method I've
> seen that returns a list is .findall(string), but then I get back the
> groups as tuples, which is sort of a problem.
Do you want something like this?
py> re.findall(r"([a-z]+)([0-9]+)", "foo bar3 w000 no abc123")
[('bar', '3'), ('w', '000'), ('abc', '123')]
py> re.findall(r"(([a-z]+)([0-9]+))", "foo bar3 w000 no abc123")
[('bar3', 'bar', '3'), ('w000', 'w', '000'), ('abc123', 'abc', '123')]
py> groups = re.findall(r"(([a-z]+)([0-9]+))", "foo bar3 w000 no abc123")
py> groups
[('bar3', 'bar', '3'), ('w000', 'w', '000'), ('abc123', 'abc', '123')]
py> [group[0] for group in groups]
['bar3', 'w000', 'abc123']
--
Gabriel Genellina
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