I have the following two identical clients
#test1.py:-----------
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = 'localhost'
port = 5052 #server port
s.connect((host, port))
print s.getsockname()
response = []
while 1:
piece = s.recv(1024)
if piece == '':
break
response.append(piece)
#test3.py:----------------
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = 'localhost'
port = 5052 #server port
s.connect((host, port))
print s.getsockname()
response = []
while 1:
piece = s.recv(1024)
if piece == '':
break
response.append(piece)
and this basic server:
#test2.py:--------------
import socket
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
host = ''
port = 5052
s.bind((host, port))
s.listen(5)
while 1:
newsock, client_addr = s.accept()
print "orignal socket:", s.getsockname()
print "new socket:", newsock.getsockname()
print "new socket:", newsock.getpeername()
print
I started the server, and then I started the clients one by one. I
expected both clients to hang since they don't get notified that the
server is done sending data, and I expected the server output to show
that accept() created two new sockets. But this is the output I got
from the server:
original socket: ('0.0.0.0', 5052)
new socket, self: ('127.0.0.1', 5052)
new socket, peer: ('127.0.0.1', 50816)
original socket: ('0.0.0.0', 5052)
new socket, self: ('127.0.0.1', 5052)
new socket, peer: ('127.0.0.1', 50818)
The first client I started generated this output:
('127.0.0.1', 50816)
And when I ran the second client, the first client disconnected, and
the second client produced this output:
('127.0.0.1', 50818)
and then the second client hung. I expected the server output to be
something like this:
original socket: ('127.0.0.1', 5052)
new socket, self: ('127.0.0.1', 5053)
new socket, peer: ('127.0.0.1', 50816)
original socket: ('0.0.0.0', 5052)
new socket, self: ('127.0.0.1', 5054)
new socket, peer: ('127.0.0.1', 50818)
And I expected both clients to hang. Can someone explain how accept()
works?
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