The following code has me mystified: In [4]: class A(object): ...: def show(self): ...: print 'hello' ...: ...: In [5]: a = A() In [6]: In [7]: x = a.show In [8]: y = getattr(a, 'show') In [9]: x Out[9]: <bound method A.show of <__main__.A object at 0xb557d0>> In [10]: y Out[10]: <bound method A.show of <__main__.A object at 0xb557d0>> In [11]: In [12]: id(x) Out[12]: 12419552 In [13]: id(y) Out[13]: 12419872 In [14]: In [15]: x is y Out[15]: False In [16]: In [17]: x() hello In [18]: y() hello
Basically, the above code is saying that foo.foobar is not the same as getattr(foo, 'foobar'). But the documentation at http://docs.python.org/lib/built-in-funcs.html#l2h-33 says that they are equivalent. And, the following seems even worse: >>> id(getattr(a, 'show')) == id(a.show) True >>> getattr(a, 'show') is a.show False What gives? This breaks my understanding of id(), the is operator, and getattr(). Can someone help me make sense of this? I'm using Python 2.5.2. - Dave -- Dave Kuhlman http://www.rexx.com/~dkuhlman -- http://mail.python.org/mailman/listinfo/python-list
