Peter Otten wrote:
If the OP insists in not examining a[0] and a[1], this will do exactly the same as the while version:Rogério Brito wrote:i = 2 while i <= n: if a[i] != 0: print a[i] i += 1You can spell this as a for-loop: for p in a: if p: print p It isn't exactly equivalent, but gives the same output as we know that a[0] and a[1] are also 0.
for p in a[2:]: if p: print p Cheers, RB -- http://mail.python.org/mailman/listinfo/python-list