On May 12, 1:30 pm, John Machin <[EMAIL PROTECTED]> wrote:
> Duncan Booth wrote:
[...]
> > I think the variant I came up with is a bit clearer:
>
> > for i in range(1,101):
> > print '%s%s' % ('' if i%3 else 'Fizz', '' if i%5 else 'Buzz') or i
>
> More than a bit clearer, IMO. How about
> print ('' if i%3 else 'Fizz') + ('' if i%5 else 'Buzz') or i
> (or perhaps
> print (('' if i%3 else 'Fizz') + ('' if i%5 else 'Buzz')) or i
> to save looking up the precedence rules) ?
Stuff clarity! How about
for i in xrange(1, 101):
print 'FizzBuzz'[4*(i%3>0):4+4*(i%5<1)] or i
--
Arnaud
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