Re: Building Time Based Bins

[Michael Spencer]

MCD wrote:
Hi Michael, thanks for responding. I actually don't use a method to get
each bin... 
That's because you picked the wrong suggestion ;-)  No, seriously, you can do it 
easily with this approach:

the bin outputs are nested in the loop. Here's my code:

data_file = open('G:\file.txt')
DUMMY = 9999
bintm = DUMMY
bins = []
for line in data_file:
    fields = line.strip().split()
    if not line: continue
    ilist = [int(time), int(a)]
(BTW, there must be more to your code than you have shared for the above line to 
execute without raising an exception - where are 'time' and 'a' initially bound?
BTW2, 'time' is the name of a stdlib module, so it's bad practice to use it as 
an identifier)
#    print "ilist:", ilist
    klock, a = ilist
    newbintm = ((klock + 4) // 5 * 5 ) % 2400
    print "bintm = %d, newbintm = %d, a = %d" % (bintm, newbintm, a)
# the above is the raw data and now the bin loop
    if bintm == 9999:
        bintm = newbintm
        binlo = a
    elif bintm == newbintm:
        binlo = min(binl, t)
    else:
        print "  ==>> %04d %2d" % (bintm, binl) ## this is the bin
This is where you've declared that you have a bin, so add it to the bins cache:
        bins.append((bintm, binl))
        bintm = newbintm
        binl = a
Michael
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