On Sat, 2008-05-24 at 15:59 -0700, zxo102 wrote:
> But this is not "\xED\x6F\x3C\x01". I need it for
> struct.unpack('f',"\xED\x6F\x3C\x01") to calculate the decimal value
> (IEEE 754).
> Any other suggestions?
>
> ouyang
>
In fact it is exactly the same string. The repr of a string always
substitutes ascii values for their numeric equivalent, but those bytes
are still the underlying representation of the string.
>>> [hex(ord(c)) for c in "\xefo<\x01"]
['0xef', '0x6f', '0x3c', '0x1']
Cheers,
Cliff
> On 5月25日, 上午6时46分, Sebastian 'lunar' Wiesner <[EMAIL PROTECTED]>
> wrote:
> > -----BEGIN PGP SIGNED MESSAGE-----
> > Hash: SHA1
> >
> > [ zxo102 <[EMAIL PROTECTED]> ]
> >
> > > how to change the hexadecimal 'ED6F3C01' (or 'ED 6F 3C 01') to
> > > "\xED\x6F\x3C\x01" in python coding?
> > > When I take 'ED6F3C01' as a string and insert '\x' into it, I just got
> > > the error information : invalid \x escape.
> >
> > [1]--> 'ED6F3C01'.decode('hex')
> > Out[1]: '\xedo<\x01'
> >
> > - --
> > Freedom is always the freedom of dissenters.
> > (Rosa Luxemburg)
> > -----BEGIN PGP SIGNATURE-----
> > Version: GnuPG v2.0.9 (GNU/Linux)
> >
> > iEYEARECAAYFAkg4mtEACgkQn3IEGILecb7W6ACeNwr/vavkaXluvc0zeSa4cy1N
> > YFIAoJjMsrRcLhqAPRxKktUqt7miMTrs
> > =jxll
> > -----END PGP SIGNATURE-----
>
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