Arrgh. One of those days where I find an answer just after posting. I spend hours on the code below only to find I don't know how to use split to it's fullest.
>>> b.strip(",").split(",") ['I', 'G', 'AQ', 'ET', 'K', 'BF'] "Poppy" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > I'm reading from a database a column that has a list of codes (comma > seperated). When I read in the list I have a single value, see code sample > below values for a, b, and c. These represent possible values in my > database. I need to loop through each value so I can expand my data from > this compressed view. > > My code below works and creates my desired output but I believe there must > be a better way this is very messy. My messy function that I'd like to > replace is lst_codes(codes). Any alternative suggestions? > > this is what I begin with > a = ',P,' > b = ',I,G,AQ,ET,K,BF,' > c = ',DZ,' > this is what I want (lists or tuples are fine) > ['P'] > ['I', 'G', 'AQ', 'ET', 'K', 'BF'] > ['DZ'] > > > def lst_codes(codes): > """ turn a string of comma seperated codes into a real list object """ > i = 0 > lstD = [] > while i < len(codes): > a = codes[i] > b = "," > if (i + 1) < len(codes): > b = codes[i + 1] > i = i + 1 > else: > b = "," > > if b <> ",": > lstD.append(a + b) > i = i + 2 > else: > lstD.append(a) > i = i + 1 > return lstD > > > a = ',P,' > b = ',I,G,AQ,ET,K,BF,' > c = ',DZ,' > > for ea in (a,b,c): > print lst_codes(ea.strip(",")) > > -- http://mail.python.org/mailman/listinfo/python-list