On Jun 27, 11:09 am, John Machin <[EMAIL PROTECTED]> wrote: > On Jun 27, 5:27 pm, cakomo <[EMAIL PROTECTED]> wrote: > > > On Jun 27, 3:06 am, John Machin <[EMAIL PROTECTED]> wrote: > > > new_line = re.sub(r'.\x08', old_line, '') > > > > new_line = re.sub(r'[^\x08]\x08', '', old_line) > > > Thanks John > > I will try it but, do you think regex replacement gonna erase the > > prev. char.? > > Yair i think its gunna y do u ask?
Sorry John Did i said i am a newbie still trying to figure out. But regex statement is really what i want. Thank you very much :) -- http://mail.python.org/mailman/listinfo/python-list
