> -----Original Message-----
> From: [EMAIL PROTECTED] [mailto:python-
> [EMAIL PROTECTED] On Behalf Of
> [EMAIL PROTECTED]
> Sent: Tuesday, July 01, 2008 2:29 AM
> To: python-list@python.org
> Subject: How make regex that means "contains regex#1 but NOT regex#2"
> ??
>
> I'm looking over the docs for the re module and can't find how to
> "NOT" an entire regex.
>
> For example.....
>
> How make regex that means "contains regex#1 but NOT regex#2" ?
>
Match 'foo.*bar', except when 'not' appears between foo and bar.
import re
s = 'fooAAABBBbar'
print "Should match:", s
m = re.match(r'(foo(.(?!not))*bar)', s);
if m:
print m.groups()
print
s = 'fooAAAnotBBBbar'
print "Should not match:", s
m = re.match(r'(foo(.(?!not))*bar)', s);
if m:
print m.groups()
== Output ==
Should match: fooAAABBBbar
('fooAAABBBbar', 'B')
Should not match: fooAAAnotBBBbar
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