Le Wednesday 02 July 2008 15:39:51 noydb, vous avez écrit : > Can someone help me with this script, which I found posted elsewhere? > I'm trying to figure out what is going on here so that I can alter it > for my needs, but the lack of descriptive names is making it > difficult. And, the script doesn't quite do anything worthwhile -- it > unzips one file from a zipfile, not all files in a zipfile. > > *** > import zipfile, os, sys, glob > > os.chdir("C:\\Temp") > zips = glob.glob('*.zip') > > for fzip in zips: > if zipfile.is_zipfile(fzip): > print fzip," is a zip" > z = zipfile.ZipFile(fzip,'r') > lstName = z.namelist() > sHgt = lstName[0] > print "Unpacking",sHgt > hgt = z.read(sHgt) > fHgt = open(sHgt,'wb') > fHgt.write(hgt) > # fHgt.flush > fHgt.close > print "Finished" > *** > > I changed it somewhat to > &&& > import zipfile, os, sys > > event_zip = ("C:\\Temp\\data4event.zip") > > z = zipfile.ZipFile(event_zip, 'r') > > zList = z.namelist() > > for zItem in zList: > print "Unpacking",zItem > zRead = z.read(zItem) > z1File = open(zItem,'wb') > z1File.write(zRead) > z1File.close
namelist() returns a list of relative file names, so you can just put them anywhere you want with: zlFile = open(os.path.join(DESTDIR, zItem), 'wb') or change the current directory, but the first way should be preferred. > print "Finished" > &&& > > This works, but I want to be able to specify a different output > location. > -- Cédric Lucantis -- http://mail.python.org/mailman/listinfo/python-list