Amir wrote:
> How do you filter keyword arguments before passing them to a function?
>
> For example:
>
> def f(x=1): return x
>
> def g(a, **kwargs): print a, f(**kwargs)
>
> In [5]: g(1, x=3)
> 1 3
>
> In [6]: g(1, x=3, y=4)
> TypeError: f() got an unexpected keyword argument 'y'
>
> Is there a way to do something like:
>
> def g(a, **kwargs): print a, f(filter_rules(f, **kwargs))
>
> so only {'x': 3} is passed to f?
I think you have to come up with something yourself. Here's a start:
import inspect
def filter_kw(f, **kw):
names = inspect.getargspec(f)[0]
return dict((n, kw[n]) for n in names if n in kw)
Peter
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