Hi Peter,
In your code s would print first_char(of the last word)+"
"+missing_word(the last word) I was looking all.
Best Regards,
Subhabrata.
SUBHABRATA wrote:
> Sorry if I didn't say that.
> The input is a string "Petrol Helium Heaven Sky"
> Now, in a3 it is "God Goddess Heaven Sky" is there,
> it is matching Heaven and Sky but not Petrol and Helium as they are
> not in a3.
> Now, as per the code it is giving me an output "S" of "Sky" and
> "Helium"
> But I was looking for an output of "H S Petrol Helium" and not "S
> Helium" meaning all the values of a5 and a6 will be concatenated in s.
> Best Regards,
> Subhabrata..
>
> Marc 'BlackJack' Rintsch wrote:
> > On Fri, 18 Jul 2008 01:31:59 -0700, SUBHABRATA wrote:
> >
> > > def try2(n):
> > > a1=raw_input("PRINT A STRING:")
> > > a2=a1.split()
> > > a3="God Godess Heaven Sky"
> > > for x in a2:
> > > a4=a3.find(x)
> > > if a4>-1:
> > > a5=a3[a4]
> > > print a5
> > > elif a4<0:
> > > a6=x
> > > print "It is not found"
> > > print a6
> > > else:
> > > print "Error"
> > > s=a5+" "+a6
> > > print s
> > >
> > > Here, if I put a string like:
> > > Petrol Helium Heaven Sky
> > > In s it is giving me S Helium
> > > But I am looking for an output of a5 and a6 concatenating all its
> > > values not the last ones. Can you suggest me any help? Am I missing
> > > any minor point?
> >
> > Maybe you should describe what the input looks like and what output you
> > want to have and how the input and output are connected. In words, not in
> > not very clear code with "numbered names". That's a silly idea and makes
> > understanding the code very hard. Please use meaningful names!
> >
> > Ciao,
> > Marc 'BlackJack' Rintsch
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