Andrew wrote:
bukzor wrote:
I have to go into these convulsions to get the directory that the
script is in whenever I need to use relative paths. I was wondering if
you guys have a better way:
...
If you just need the current path (where it is executed) why not use
os.getcwd()
which returns a string of the absolute path to the module being executed.
$ echo "print __file__" > path.py
$ ipython
In [1]: import path
path.pyc
In [2]: import os
In [3]: os.path.join(os.getcwd(), path.__file__.rstrip("c"))
Out[3]: '/home/andrew/path.py'
--
Andrew
I was thinking of this in the module being imported, but now that I try,
it doesn't work. It is still seeing itself from the symlink's position.
This works, in the module being imported:
$ less path.py
from os.path import realpath
here = realpath(__file__.rstrip("c"))
$ python
>>> import path
>>> path.here
'/home/andrew/sym/sym/path.py'
--
Andrew
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