On Mon, Jul 28, 2008 at 5:45 AM, Scott David Daniels
<[EMAIL PROTECTED]> wrote:
> Alan Franzoni wrote:
>>
>> Michael Torrie was kind enough to say:
>>
>>> Of course any time you send coherent numbers over the network, I highly
>>> recommend you use what's called network byte order.... I'm sure python
>>> has some convention in the struct module for dealing with this.
>>
>> Not in the struct module; such functions are available in the socket
>> module, and should be employed indeed.
>
> Please don't pass this misinformation along.
>
> In the struct module document, see the section on the initial character:
> Character Byte order Size and alignment
> @ native native
> = native standard
> < little-endian standard
> > big-endian standard
> ! network (= big-endian) standard
> and notes @ is the default.
>>>> print struct.pack('<lh', 3,4)
>>>> print struct.pack('>lh', 3,4)
>>>> print struct.pack('lh', 3,4)
>>>> print struct.pack('!lh', 3,4)
thanks for clarifying, and just to make sure, i am using '!' format
from the struct package... i had this even in my previous email....
what am doing below is fine right?
this is short
>>> struct.pack('!h',3)
'\x00\x03'
this is integer
>>> struct.pack('!i',3)
'\x00\x00\x00\x03'
this is long
>>> struct.pack('!l',3)
'\x00\x00\x00\x03'
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