On Aug 11, 6:24 pm, "Calvin Spealman" <[EMAIL PROTECTED]> wrote: > for k in foo: > foo[k] += bar.get(k, 0)
An alternative: for k in bar: foo[k] += bar[k] The OP asserts that foo keys are a superset of bar keys. If that assertion is not true (i.e. there are keys in bar that are not in foo, your code will silently ignore them whereas mine will cause an exception to be raised (better behaviour IMHO). If the assertion is true, mine runs faster (even when len(foo) == len(bar). -- http://mail.python.org/mailman/listinfo/python-list
