On Aug 12, 4:59 am, "Gabriel Genellina" <[EMAIL PROTECTED]>
wrote:
> En Mon, 11 Aug 2008 19:19:19 -0300, tow <[EMAIL PROTECTED]>
> escribi :
>
> > I have a python script (part of a django application, if it makes any
> > difference) which is exhibiting the following behaviour:
>
> > import my_module # succeeds
> > imp.find_module("my_module") # fails, raising ImportError
>
> > which is completely baffling me. According to sys.path, both should
> > fail; the directory containing my_module is not in sys.path (though
> > the my_module directory itself is).
>
> my_module is not a module but a package, right? Else I don't understand
> the above statement.
Sorry, sloppy terminology on my part, yes, my_module is a package.
> > More puzzlingly, printing out
> > my_module.__file__ gives:
>
> > /home/tow/test/my_module/../my_module/__init__.pyc
>
> > I don't really understand what the ".." is doing in there.
>
> > Can someone explain what I'm missing here, it's got me stumped.
>
> Perhaps you have ".." in sys.path? And the current directory happens to be
> /home/tow/test/my_module?
The current directory is actually a subdirectory of /home/tow/test/
my_module,
but ".." is not in sys.path (nor is anything containing "..") In any
case, if
it were a matter of sys.path, surely the imp.find_module call above
should succeed?
Basically, I had thought that import and imp.find_module used exactly
the same
search path, but the above example shows that at least in this
circumstance they
don't; import is picking up additional search paths from somewhere -
what am I missing?
Toby
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