Dave napisał(a): > Hey there, having a bit of problem iterating through lists before i go > on any further, here is > a snip of the script. > -- > d = "a1 b1 c1 d1 e1 a2 b2 c2 d2 e2 a3 b3 c3 d3 e3 a4 b4 c4 d4 e4 a5 b5 > c5 d5 e5" > inLst = d.split() > hitLst = [] > > hitNum = 0 > stopCnt = 6 + hitNum > > for i in range(hitNum,len(inLst), 1): > if i == stopCnt: break > hitLst.append(inLst[i]) > > print hitLst > -- > $ python helper.py > ['a1', 'b1', 'c1', 'd1', 'e1', 'a2'] > > > This works fine for my purposes, what I need is an outer loop that > goes through the original list again and appends my next request. > > ie. > > hitNum = 5 > > which will return: > > ['a2', 'b2', 'c2', 'd2', 'e2', 'a3'] > > and append it to the previous one. > > ie: > > ['a1', 'b1', 'c1', 'd1', 'e1', 'a2'] > ['a2', 'b2', 'c2', 'd2', 'e2', 'a3'] > > > not really sure how to do this right now though, been trying several > methods with no good results. > > btw, just creating lagged values (sort of shift registers) on the > incoming signal > > Many thanks, > > Dave
It seems you're going through a lot of trouble just to construct the list by hand. Why don't you try slicing? > d = "a1 b1 c1 d1 e1 a2 b2 c2 d2 e2 a3 b3 c3 d3 e3 a4 b4 c4 d4 e4 a5 b5 c5 d5 > e5" > in_lst = d.split() > hit_lst = in_lst[0:6] > hit_lst_2 = in_lst[5:11] Regards, Marek -- http://mail.python.org/mailman/listinfo/python-list
