"W. eWatson" <[EMAIL PROTECTED]> writes:
> [a.dat, c.dat, g.dat, k.dat, p.dat]
> [a.txt, b.txt, g.txt, k.txt r.txt, w.txt]
>
> What I need is to pair up items with the same prefix and use "None",
> or some marker, to indicate the absence of the opposite item.
This is functionally influenced but should be straightforward:
dat = ['a.dat', 'c.dat', 'g.dat', 'k.dat', 'p.dat']
txt = ['a.txt', 'b.txt', 'g.txt', 'k.txt', 'r.txt', 'w.txt']
# just get the portion of the filename before the first period
def prefix(filename):
return filename[:filename.find('.')]
# make a dictionary mapping prefixes to filenames
def make_dict(plist):
return dict((prefix(a),a) for a in plist)
pdat = make_dict(dat)
ptxt = make_dict(txt)
# get a list of all the prefixes, use "set" to remove
# duplicates, then sort the result and look up each prefix.
for p in sorted(set(pdat.keys() + ptxt.keys())):
print pdat.get(p), ptxt.get(p)
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