On Sep 11, 10:36 am, Nick Craig-Wood <[EMAIL PROTECTED]> wrote: >I'd type the explicit > > v1,v2,v3 = mydict['one'], mydict['two'], mydict['two'] # 54 chars > Either > is only a couple more > characters to type. It is completely > explicit and comprehensible to everyone, in comparison to > > v1,v2,v3 = [ mydict[k] for k in ['one','two','two']] # 52 chars > v1,v2,v3 = [ mydict[k] for k in 'one two two'.split()] # 54 chars > > Unlike perl, it will also blow up if mydict doesn't contain 'one' > which may or may not be what you want. >
Is your above solution robust against undefined keys. In my example it would'nt be a problem. The dict would be fully populated, but I'm just curious. -- http://mail.python.org/mailman/listinfo/python-list
