En Wed, 01 Oct 2008 08:11:29 -0300, Igor Kaplan
<[EMAIL PROTECTED]> escribió:
I got quite unusual problem and all my searches to find the answer on
my
own were not successful.
Here is the scenario:
I have the python program, let's call it script1.py, this program
needs to
execute another python script, let's call it script2.py.
In script1.py I have the statement:
execfile('script2.py')
Everything is fine beside one thing. The script2.py is pretty big
python
program which does a lot of things and also while runs, it modifies many
variables and module members, such for example as sys.path. So when
script2.py exits all changes which it does are visible in my main
program,
script1.py. Even more, I need to execute script2.py in loop, several
times
during script1.py session. And all changes, which script2.py does just
accumulate.
I wander, is there any way to execute script2.py in it's own
environment,
so when script2.py exits, all modifications, which it is done in global
modules are gone?
If you want a true isolated execution, start a new Python process:
subprocess.call([sys.executable, "script2.py"])
But I feel this is not the right thing to do - instead of *executing* many
times script2.py, maybe you have to *import* some functions or classes
from it, and then use them.
--
Gabriel Genellina
--
http://mail.python.org/mailman/listinfo/python-list
